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Estimation, Estimates and Estimators

Ordinary Least Squares for a Single Mean​

If μ\mu is unknown and xi,…,xnx_i,\ldots,x_n are data, we can estimate μ\mu by finding

min⁡μ∑i=1n(xi−μ)2\min_{\mu} \displaystyle\sum_{i=1}^{n}(x_i-\mu)^2

In this case the resulting estimate is simply

μ=x‾\mu = \overline{x}

and can easily be derived by setting the derivative to zero.

Examples​

Example

Consider the numbers x1,…,x5x_1, \ldots, x_5 to be

13,7,4,16 and 913,7,4,16 \textrm{ and } 9

We can plot ∑(xi−μ)2\displaystyle\sum(x_i-\mu)^2 vs. μ\mu and find the minimum.

Maximum Likelihood Estimation​

If (Y1,…,Yn)′\left (Y_1, \ldots, Y_n\right )' is a random vector from a density fθf_{\theta} where θ\theta is an unknown parameter, and y\mathbf{y} is a vector of observations then we define the likelihood function to be

Ly(θ)=fθ(y)L_{\mathbf{y}}(\theta)=f_{\theta}(y)

Examples​

Example

If x1,…,xnx_1,\ldots,x_n are assumed to be observations of independent random variables with a normal distributions and mean of μ\mu and variance of σ2\sigma^2, then the joint density is

f(x1)⋅f(x2)⋅…⋅f(xn)f(x_1)\cdot f(x_2)\cdot\ldots\cdot f(x_n)

=12πσe−(x1−μ)22σ2⋅…⋅12πσe−(xn−μ)22σ2= \displaystyle\frac{1}{\sqrt{2\pi}\sigma}e^{-\displaystyle\frac{(x_1-\mu)^2}{2\sigma^2}} \cdot \ldots\cdot \displaystyle\frac{1}{\sqrt{2\pi}\sigma}e^{-\displaystyle\frac{(x_n-\mu)^2}{2\sigma^2}}

=Πi=1n12πσe−(xi−μ)22σ2=\Pi_{i=1}^n \displaystyle\frac{1}{\sqrt{2\pi}\sigma}e^{-\displaystyle\frac{(x_i-\mu)^2}{2\sigma^2}}

=1(2π)n/2σne−12σ2∑i=1N(xi−μ)2=\displaystyle\frac{1}{(2\pi)^{n/2}\sigma^n}e^{-\displaystyle\frac{1}{2\sigma^2}\displaystyle\sum_{i=1}^N(x_i-\mu)^2}

and if we assume σ2\sigma^2 is known then the likelihood function is

L(μ)=1(2π)n/2σne−12σ2Σi=1N(xi−μ)2L(\mu)=\displaystyle\frac{1}{(2\pi)^{n/2}\sigma^n}e^{-\displaystyle\frac{1}{2\sigma^2}\Sigma_{i=1}^N(x_i-\mu)^2}

Maximizing this is done by maximizing the log, i.e. finding the μ\mu for which:

ddμln⁡L(μ)=0,\displaystyle\frac{d}{d\mu}\ln L(\mu)=0,

which again results in the estimate

μ^=x‾\hat{\mu}=\overline{x}

Detail​

Definition

If (Y1,…,Yn)′\left (Y_1, \ldots, Y_n\right )' is a random vector from a density fθf_{\theta} where θ\theta is an unknown parameter, and y\mathbf{y} is a vector of observations then we define the likelihood function to be

Ly(θ)=fθ(y)L_{\mathbf{y}}(\theta)=f_{\theta}(y)

Ordinary Least Squares​

Consider the regression problem where we fit a line through (xi,yi)(x_i,y_i) pairs with x1,…,xnx_1, \ldots, x_n fixed numbers but where yiy_i is measured with error.

Fig. 36

Figure: Regression line through data pairs.

Details​

The ordinary least squares (OLS) estimates of the parameters α\alpha and β\beta in the model yi=α+βxi+ϵiy_i=\alpha + \beta x_i + \epsilon_i are obtained by minimizing the sum of squares

∑i(yi−(α+βxi))2\displaystyle\sum_i \left ( y_i -(\alpha +\beta x_i) \right )^2

a=y‾−bx‾b=∑i=1n(xi−x‾)(yi−y‾)∑i=1n(xi−x‾)2\begin{aligned} a &= \overline{y} - b\overline{x} \\ \\ b &= \displaystyle\frac{\displaystyle\sum^n_{i=1} (x_i-\overline{x})(y_i-\overline{y})}{\displaystyle\sum^n_{i=1} (x_i-\overline{x})^2} \end{aligned}

Random Variables and Outcomes​

Details​

Recall that X1,…,XnX_1, \ldots, X_n are random varibles (reflecting the population distribution) and x1,…,xnx_1, \ldots, x_n are numerical outcomes of these distributions. We use upper case letters to denote random variables and lower case letters to denote outcome or data.

Examples​

Example

Let the mean of a population be zero and the σ=4\sigma=4. Then draw three samples from this population with size, nn, either 44, 1616 or 6464. The sample mean Xˉ\bar{X} will have a distribution with mean zero and standard deviation of σn\displaystyle\frac{\sigma}{\sqrt{n}} where n=4n= 4, 1616 or 6464.

Estimators and Estimates​

In OLS regression, note that the values of aa and bb:

a=y‾−bx‾a = \overline{y} - b \overline{x}

b=Σi=1n(xi−x‾)(yi−y‾)Σi=1n(xi−x‾)2b = \displaystyle\frac{\Sigma_{i=1}^{n} (x_i - \overline{x}) (y_i - \overline{y})}{\Sigma_{i=1}^{n} (x_i - \overline{x})^2}

are outcomes of random variables e.g. bb is the outcome of

β^=Σi=1n(xi−x‾)(Yi−Y‾)Σi=1n(xi−x‾)2\hat{\beta} = \displaystyle\frac{\Sigma_{i=1}^{n} (x_i - \overline{x}) (Y_i - \overline{Y})}{\Sigma_{i=1}^{n} (x_i - \overline{x})^2}

the estimator which has some distribution.

Fig. 37

Figure: Shows an example of the distribution of the estimator β^\hat{\beta}

Details​

The following R commands can be used to generate a distribution for the estimator β^\hat{\beta}

library(MASS)
nsim <- 1000
betahat <- NULL
for (i in 1:nsim) {
n <- 20
x <- seq(1:n) # Fixed x vector
y <- 2 + 0.4*x + rnorm(n, 0, 1)
xbar <- mean(x)
ybar <- mean(y)
b <- sum((x-xbar)*(y-ybar))/sum((x-xbar)^2)
a <- ybar - b * xbar
betahat <- c(betahat, b)
}
truehist(betahat)